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It's not that complicated. Ascii characters are represented by numbers, so that, for example: mov al, 'A';actually moves the number 65 into al, because that's its ascii code mov al, 'B';actually moves the number 66 into al mov al, C';moves 67 into al, and so on. In the case of the numerals it's: mov al, '0';moves the number 48 into al mov al, '1';moves the number 49 into al mov al, '2';moves the number 50 into al mov al, '3';moves the number 51 into al So if you subtract 48 from any of those four, you get 0, 1, 2 and 3 respectively - the conversion you want. Thanks for your reply:) here the code start: read A0 push A0; save A0 push A1; save A1 load_fp A1 8; load parameter C; compare to ASCII I to M load_c A0 73; ASCII I subtract A1 A0; A1 = int(C) jmpn A1 outof move A1 A0; copy it load_c A1 M; max value subtract A1 A0; A1 = M - int(C) jmpn A1 outof; return result store_fp A0 6; result endDA:; restore accumulators pop A1 pop A0 return outof:; return -ve store_fp A1 6; -ve jump endDA I:.data 2 73 V:.data 2 86 X:.data 2 88 L:.data 2 76 C:.data 2 67 D:.data 2 68 M:.data 2 77.